这篇文章主要教大家如何简单实现ajax拖拽上传文件,具有一定的参考价值,感兴趣的小伙伴们可以参考一下

AJAX拖拽上传功能实现,供大家参考,具体内容如下

<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1.0"> <meta http-equiv="X-UA-Compatible" content="ie=edge"> <title>Document</title> <style> .box { width: 300px; height: 300px; border: 1px solid #000; text-align: center; line-height: 300px; font-size: 40px; } </style> </head> <body> <p class="box">+</p> <script> var box = document.querySelector('.box'); box.ondragover = function (e) { e.preventDefault(); } box.ondrop = function (e) { console.log(e.dataTransfer) e.preventDefault(); var xhr = new XMLHttpRequest(); xhr.onreadystatechange = function () { if (xhr.readyState == 4 && xhr.status == 200) { console.log(xhr.responseText) } } xhr.open('POST', './server.php', true); var formdata = new FormData(); formdata.append('pic', e.dataTransfer.files[0]); formdata.append('name', 'luyao'); xhr.send(formdata); } </script> </body> </html>

//server.php

<?php $rand = rand(1,1000).'.jpg'; move_uploaded_file($_FILES['pic']['tmp_name'], './uploads/'.$rand); echo '/uploads/'.$rand;

上面是我整理给大家的,希望今后会对大家有帮助。

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