最近完成了一个nodejs+mongoose的项目,碰到了mongodb的级联查询操作。情形是实现一个排行榜,查看某个公司(organization)下属客户中发表有效文ruan章wen最多的前十人。

Account表:公司的信息单独存在一个account表里。

var AccountSchema = new Schema({ loginname: {type: String}, password: {type: String}, /** * 联系方式 */ //账户公司名 comName: {type: String}, //地址 address: {type: String}, //公司介绍 intro: {type: String} }); mongoose.model('Account', AccountSchema);

Cusomer表:公司的客户群。

var CustomerSchema = new Schema({ /** * 基本信息 */ //密码 password: {type: String}, //归属于哪个Account belongToAccount: {type: ObjectId, ref: 'Account'}, //手机号,登录用 mobile: {type: String}, //真实姓名 realname: {type: String} }); CustomerSchema.index({belongToAccount: 1, mobile: 1}, {unique: true}); mongoose.model('Customer', CustomerSchema);

article表

var articleSchema= new Schema({ belongToAccount: {type: ObjectId, ref: 'Account'}, title: {type: String}, text: {type: String}, createTime: {type: Date, default: Date.now}, author: {type: ObjectId, ref: 'Customer'}, //0,待确认,1 有效 ,-1 无效 status: {type: Number, default: 0} }); articleSchema.index({belongToAccount: 1, createTime:-1,author: 1}, {unique: false}); mongoose.model('article', articleSchema);

这里要做的就是,由accountId→aggregate整理软文并排序→级联author找到作者的姓名及其他信息。

代码如下:

exports.getRankList = function (accountid, callback) { AticleModel.aggregate( {$match: {belongToAccount: mongoose.Types.ObjectId(accountid), status: 1}}, {$group: {_id: {customerId: "$author"}, number: {$sum: 1}}}, {$sort: {number: -1}}).limit(10).exec(function (err, aggregateResult) { if(err){ callback(err); return; } var ep = new EventProxy(); ep.after('got_customer', aggregateResult.length, function (customerList) { callback(null, customerList); }); aggregateResult.forEach(function (item) { Customer.findOne({_id: item._id.customerId}, ep.done(function (customer) { item.customerName = customer.realname; item.customerMobile=cusomer.mobile; // do someting ep.emit('got_customer', item); })); }) }); };

返回的结果格式(这里仅有两条记录,实际为前十):

[ { _id: { customerId: 559a5b6f51a446602032fs21 }, number: 5, customerName: 'test2', mobile:22 } , { _id: { customerId: 559a5b6f51a446602041ee6f }, number: 1, customerName: 'test1', mobile: 11 } ]

上面是我整理给大家的,希望今后会对大家有帮助。

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